how do I create a job from a graph without using .to_job?

Based on the documentation, the primary way to create a job from a graph is by using the

.to_job()

method. This method allows you to convert a graph into an executable job by providing the necessary components required for execution, such as resources, configuration, and other environment-specific features. Here is an example from the documentation:

python @graph def my_graph():     ...  my_job = my_graph.to_job()

If you are looking for an alternative way to create a job from a graph without directly using

.to_job()

, you might consider using the

@job

decorator. You can define a job that includes the graph within its body. Here's an example:

python @graph def my_graph():     ...  @job def my_job():     my_graph()

In this case, the

@job

decorator is used to define a job that includes the invocation of the graph. This is effectively another way to create a job from a graph, but it still relies on the graph being defined and then invoked within the job. If you have a specific use case or constraint that prevents you from using

.to_job()

or the

@job

decorator, please provide more details so that I can better assist you.