We re wanting to build new pipelines using the ` op` and ` g

Question

We re wanting to build new pipelines using the ` op` and ` graph` decorators to future proof them I m having trouble with including a new graph in an existing repo as the repository is expecting a PipelineDefinition to be returned ```grpc channel MultiThreadedRendezvous lt MultiThreadedRendezvous of RPC that terminated with status = StatusCode UNKNOWN details = Exception iterating responses Invariant failed Description Bad constructor for pipeline gpdc identification roster to snowflake graph must return PipelineDefinition got value of type lt class dagster core definitions graph GraphDefinition gt debug error string = created 1632515755 844435000 description Error received from peer ipv4 172 22 0 5 4003 file src core lib surface call cc file line 1067 grpc message Exception iterating responses Invariant failed Description Bad constructor for pipeline gpdc identification roster to snowflake graph must return PipelineDefinition got value of type lt class dagster core definitions graph GraphDefinition gt grpc status 2 gt ```

Andrew Brown · Answer

``` repository def miscellaneous repository return pipelines gpdc identification roster to snowflake graph lambda gpdc identification roster to snowflake graph snowflake information schema query history to s3 snowflake logs pipeline lambda snowflake information schema query history to s3 snowflake logs pipeline materialization deployment pipeline lambda materialization deployment pipeline daily tests pipeline lambda daily tests pipeline schedules schedule snowflake information schema query history to s3 snowflake logs pipeline lambda schedule snowflake information schema query history to s3 snowflake logs pipeline schedule daily tests pipeline lambda schedule daily tests pipeline sensors slack on pipeline failure lambda slack on pipeline failure ```

Andrew Brown · Answer

^^^ that s the repository code in question

Andrew Brown · Answer

Oh you know what I just answered my own question I need to use the `jobs` key in the dictionary facepalm

Andrew Brown · Answer

Friday afternoons ftw

daniel · Answer

That s right and then they also need to be jobs not graphs you can create a job from a graph with the to job function on GraphDefinition <https docs dagster io apidocs experimental job>

Andrew Brown · Answer

thumbsup thanks for the additional color