Eugenio Contreras
05/02/2023, 12:25 PM[op1, op2, op3, op4] >> op5
Is there a way to execute op5 even though one of the previous ops failed?
The code in op5 is able to handle the failures, so that's not a problem.
I want to avoid as much as I can the following pattern:
op1 >> op5
op2 >> op5
op3 >> op5
...
Thanks!yuhan
05/04/2023, 5:06 PMop5
takes one single input which is [op1, op2, op3, op4]
, and op1
can have an optional output, then when it’s [op2, op3, op4]
, it would still go through to op5
.